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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

Efficiency of a heat engine is 40%. If it takes in 5000 J of heat, work output is:

Answer: 2000 J.

  • A 500 J
  • B 1000 J
  • C 2000 J
  • D 3000 J

Correct answer: C. 2000 J

Explanation: W = efficiency x Q<sub>in</sub> = 0.4 x 5000 = 2000 J.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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