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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

Ball of mass 2 kg moving at 10 m/s hits wall and rebounds at 8 m/s. Energy lost:

Answer: 18 J.

  • A 4 J
  • B 18 J
  • C 36 J
  • D 100 J

Correct answer: B. 18 J

Explanation: KE_initial = (1/2)(2)(100) = 100 J. KE_final = (1/2)(2)(64) = 64 J. Loss = 100 - 64 = 36 J.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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