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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A uniform chain of mass 6 kg and length 3 m lies on a table with one-third of its length hanging over the edge. The work needed to pull the hanging part back onto the table is (g = 10 m/s<sup>2</sup>):

Answer: 10 J.

  • A 5 J
  • B 20 J
  • C 10 J
  • D 30 J

Correct answer: C. 10 J

Explanation: Hanging mass = 6 × 1/3 = 2 kg, length 1 m, centre of mass 0.5 m below the edge. W = mgh = 2 × 10 × 0.5 = 10 J.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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