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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A pendulum of length 1 m swings to maximum angle 60 deg from vertical. Speed at bottom (g=10):

Answer: sqrt(10) m/s.

  • A sqrt(5) m/s
  • B sqrt(10) m/s
  • C sqrt(15) m/s
  • D sqrt(20) m/s

Correct answer: B. sqrt(10) m/s

Explanation: Height dropped: h = L(1 - cos60) = 1 x (1-0.5) = 0.5 m. v = sqrt(2gh) = sqrt(2 x 10 x 0.5) = sqrt(10) m/s.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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