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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A particle of mass m is attached to spring (k). At position x from equilibrium, the total energy equals KE when:

Answer: x=0 (equilibrium).

  • A x=0 (equilibrium)
  • B x=A (amplitude)
  • C x=A/2
  • D x=A*sqrt(2)

Correct answer: A. x=0 (equilibrium)

Explanation: Total energy = KE + PE. At x=0, PE = 0, so all energy is KE. Total energy = KE only at equilibrium.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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