A particle of mass 0.5 kg moves in x-direction with F = (3x 2 + 2) N. Work from x=0 to x=3 m:

⚛️ Physics · Work, Energy and Power · NEET & JEE

A particle of mass 0.5 kg moves in x-direction with F = (3x2 + 2) N. Work from x=0 to x=3 m:

Answer: 33 J.

A 15 J
B 27 J
C 33 J
D 45 J

Correct answer: C. 33 J

Explanation: W = integral(0 to 3) (3x2+2) dx = [x3 + 2x] from 0 to 3 = 27 + 6 = 33 J.

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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A particle of mass 0.5 kg moves in x-direction with F = (3x<sup>2</sup> + 2) N. Work from x=0 to x=3 m:

Concept context

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