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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A car of mass 500 kg accelerates from 0 to 30 m/s. Work done by engine (ignoring friction):

Answer: 225000 J.

  • A 75000 J
  • B 150000 J
  • C 225000 J
  • D 450000 J

Correct answer: C. 225000 J

Explanation: W = Delta KE = (1/2)(500)(900) - 0 = 225000 J.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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