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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A car of mass 1000 kg is driven at constant speed 20 m/s by engine power 40 kW. Friction force is:

Answer: 2000 N.

  • A 800 N
  • B 1000 N
  • C 2000 N
  • D 4000 N

Correct answer: C. 2000 N

Explanation: P = F x v. F = P/v = 40000/20 = 2000 N. This equals friction at constant speed.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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