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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A body of mass m is raised through height h on a slope of angle theta. If mu is the coefficient of friction, total work done against gravity and friction is:

Answer: All of the above.

  • A mgh
  • B mgh + mu x mg x cos(theta) x (h/sin(theta))
  • C mgh(1 + mu/tan(theta))
  • D All of the above

Correct answer: D. All of the above

Explanation: Both mgh + mu.mg.cos(theta).l = mgh + mu.mg.cot(theta).h = mgh(1 + mu/tan(theta)). All 3 expressions are equivalent.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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