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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A block of 2 kg falls onto a spring (k=1000 N/m) from height 2 m above spring. Maximum compression (g=10):

Answer: 0.2 m.

  • A 0.1 m
  • B 0.2 m
  • C 0.4 m
  • D 0.5 m

Correct answer: B. 0.2 m

Explanation: Energy: mgh + mgx = (1/2)kx<sup>2.</sup> 2x10x2 + 2x10xx = 500x<sup>2.</sup> 40 + 20x = 500x<sup>2.</sup> 500x<sup>2</sup> - 20x - 40 = 0. 25x<sup>2</sup> - x - 2 = 0. x = (1 + sqrt(1+200))/50 approx 0.2 m.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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