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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A ball is projected horizontally at 20 m/s from 20 m height. KE when it hits ground (g=10, m=1 kg):

Answer: 400 J.

  • A 200 J
  • B 400 J
  • C 600 J
  • D 1000 J

Correct answer: B. 400 J

Explanation: Initial KE = (1/2)(1)(400) = 200 J. PE = mgh = 1 x 10 x 20 = 200 J. Total final KE = 200+200 = 400 J.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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