Zaymiey

⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A 2 kg block moving at 6 m/s collides head-on and sticks to a 4 kg block at rest. The kinetic energy lost in the collision is:

Answer: 24 J.

  • A 12 J
  • B 24 J
  • C 36 J
  • D 0 J

Correct answer: B. 24 J

Explanation: Common v = 12/6 = 2 m/s; KEi = 36 J, KEf = 0.5·6·4 = 12 J; loss = 24 J.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

Read the full Work, Energy and Power notes →