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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A 2 kg ball moving at 4 m/s collides head-on with a 3 kg ball at rest. If the coefficient of restitution is 0.5, the speed of the 3 kg ball after collision is:

Answer: 2.4 m/s.

  • A 2.4 m/s
  • B 1.6 m/s
  • C 0.4 m/s
  • D 3.0 m/s

Correct answer: A. 2.4 m/s

Explanation: Momentum: 8 = 2v<sub>1</sub> + 3v<sub>2</sub>. Restitution: v<sub>2</sub> - v<sub>1</sub> = 0.5×4 = 2. Solving gives v<sub>2</sub> = 2.4 m/s (and v<sub>1</sub> = 0.4 m/s).

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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