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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A 2 kg ball is dropped from 5 m. Its KE just before hitting the ground is:

Answer: 100 J.

  • A 10 J
  • B 50 J
  • C 100 J
  • D 200 J

Correct answer: C. 100 J

Explanation: KE = mgh = 2 x 10 x 5 = 100 J (all PE converted to KE in free fall).

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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