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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A 1000 kg car runs under a constant engine power of 50 kW. When its speed is 10 m/s and the resistive force is 1000 N, its acceleration is:

Answer: 4 m/s 2.

  • A 1 m/s<sup>2</sup>
  • B 4 m/s<sup>2</sup>
  • C 2 m/s<sup>2</sup>
  • D 5 m/s<sup>2</sup>

Correct answer: B. 4 m/s<sup>2</sup>

Explanation: Driving force = P/v = 50000/10 = 5000 N. Net force = 5000 - 1000 = 4000 N. a = 4000/1000 = 4 m/s<sup>2</sup>.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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