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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A 1000 kg car engine has efficiency 30% and consumes fuel at 10 kW. Maximum speed on level road with friction 500 N:

Answer: 6 m/s.

  • A 6 m/s
  • B 12 m/s
  • C 20 m/s
  • D 60 m/s

Correct answer: A. 6 m/s

Explanation: Useful power = 0.3 x 10000 = 3000 W. Max speed = P/F = 3000/500 = 6 m/s.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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