Zaymiey

⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A 1 kg block on a rough surface (μ = 0.2, g = 10 m/s²) is given an initial speed of 10 m/s. The distance it travels before stopping is:

Answer: 25 m.

  • A 12.5 m
  • B 25 m
  • C 50 m
  • D 10 m

Correct answer: B. 25 m

Explanation: d = v²/(2μg) = 100/(2·0.2·10) = 25 m.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

Read the full Work, Energy and Power notes →