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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

A 1 kg block compresses spring (k=100 N/m) by 0.2 m. Maximum speed of block when released (spring on frictionless surface):

Answer: 2 m/s.

  • A 1 m/s
  • B 2 m/s
  • C 4 m/s
  • D 10 m/s

Correct answer: B. 2 m/s

Explanation: Spring PE = (1/2)kx<sup>2</sup> = (1/2)(100)(0.04) = 2 J = KE = (1/2)mv<sup>2.</sup> v = sqrt(4) = 2 m/s.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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