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⚛️ Physics  ·  Waves  ·  NEET & JEE

A stationary source emits frequency 500 Hz. An observer moves toward it at 34 m/s (speed of sound = 340 m/s). Observed frequency:

Answer: 550 Hz.

  • A 450 Hz
  • B 500 Hz
  • C 550 Hz
  • D 600 Hz

Correct answer: C. 550 Hz

Explanation: f<sub>obs</sub> = f(v + v<sub>o</sub>)/v = 500 x (340+34)/340 = 500 x 374/340 = 550 Hz.

Standing Wave: Nodes and Antinodes (Open Pipe, 2nd Harmonic)nodenodenodeantinodeantinodeSolid and dashed lines show the string/air column at two instants - nodes never move

A standing wave forms from two identical waves travelling in opposite directions and interfering; nodes (always zero displacement) and antinodes (maximum displacement) stay fixed in place, unlike a travelling wave where the whole pattern moves.

Concept context

Wave types, superposition, standing waves, Doppler effect, and sound intensity.

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