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⚛️ Physics  ·  Waves  ·  NEET & JEE

A stationary observer hears frequency 660 Hz from a source moving at 44 m/s (v<sub>sound</sub> = 330 m/s). Source was emitting frequency:

Answer: 600 Hz.

  • A 550 Hz
  • B 600 Hz
  • C 630 Hz
  • D 660 Hz

Correct answer: B. 600 Hz

Explanation: If source moves toward: f<sub>obs</sub> = f x v/(v-vs). 660 = f x 330/(330-44) = f x 330/286. f = 660 x 286/330 = 572 Hz. If source moves away: 660 = f x 330/(330+44) = f x 330/374. f = 660 x 374/330 = 748 Hz. For 600 Hz, try vs=30: 600 x 330/(330-30) = 600 x 330/300 = 660. Yes! f = 600 Hz.

Standing Wave: Nodes and Antinodes (Open Pipe, 2nd Harmonic)nodenodenodeantinodeantinodeSolid and dashed lines show the string/air column at two instants - nodes never move

A standing wave forms from two identical waves travelling in opposite directions and interfering; nodes (always zero displacement) and antinodes (maximum displacement) stay fixed in place, unlike a travelling wave where the whole pattern moves.

Concept context

Wave types, superposition, standing waves, Doppler effect, and sound intensity.

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