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⚛️ Physics  ·  Waves  ·  NEET & JEE

A guitar string of length 80 cm is plucked. Fundamental frequency if v = 400 m/s:

Answer: 250 Hz.

  • A 200 Hz
  • B 250 Hz
  • C 400 Hz
  • D 500 Hz

Correct answer: B. 250 Hz

Explanation: String fixed at both ends: f<sub>1</sub> = v/(2L) = 400/(2 x 0.8) = 400/1.6 = 250 Hz.

Standing Wave: Nodes and Antinodes (Open Pipe, 2nd Harmonic)nodenodenodeantinodeantinodeSolid and dashed lines show the string/air column at two instants - nodes never move

A standing wave forms from two identical waves travelling in opposite directions and interfering; nodes (always zero displacement) and antinodes (maximum displacement) stay fixed in place, unlike a travelling wave where the whole pattern moves.

Concept context

Wave types, superposition, standing waves, Doppler effect, and sound intensity.

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