Zaymiey

⚛️ Physics  ·  Wave Optics  ·  NEET & JEE

In YDSE, the n-th dark fringe from centre is at distance y from centre. If the screen moves farther, what happens to y?

Answer: y increases proportionally with D.

  • A y increases proportionally with D
  • B y decreases
  • C y stays same
  • D y depends only on wavelength

Correct answer: A. y increases proportionally with D

Explanation: y<sub>dark</sub> = (2n-1)λD/(2d). Moving screen farther (increasing D) increases y. Fringe positions move farther from centre.

Young's Double Slit Experimentsourceslits S₁,S₂dscreenbrightdarkPath difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes

Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.

Concept context

Huygens principle, Young's double slit, diffraction, polarization. Essential for JEE.

Read the full Wave Optics notes →