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⚛️ Physics  ·  Wave Optics  ·  NEET & JEE

In YDSE, slits are separated by d, screen at D. A point source is placed at distance D from the slits, off-axis by y<sub>0</sub>. The central fringe shifts by:

Answer: y 0 (fringes shift toward the source).

  • A y<sub>0</sub> (fringes shift toward the source)
  • B y<sub>0</sub>/2, half the actual shift produced by the displaced source
  • C 2y<sub>0</sub>, twice the actual shift produced by the displaced source
  • D y<sub>0</sub> D/d, an expression with the wrong dependence on slit separation

Correct answer: A. y<sub>0</sub> (fringes shift toward the source)

Explanation: When source shifts by y<sub>0</sub>, the path difference to the slits changes. The central fringe (zero path difference) shifts by an amount equal to the source shift projected at the screen. For symmetric setup: shift = y<sub>0</sub> D / (distance from source to slits) = y<sub>0</sub> when source is at same distance D.

Young's Double Slit Experimentsourceslits S₁,S₂dscreenbrightdarkPath difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes

Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.

Concept context

Huygens principle, Young's double slit, diffraction, polarization. Essential for JEE.

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