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⚛️ Physics  ·  Wave Optics  ·  NEET & JEE

In single-slit diffraction, the intensity at angle θ from centre follows I = I<sub>0</sub> (sinα/α)² where α = πa sinθ/λ. At what value of α is the first secondary maximum approximately?

Answer: 3π/2.

  • A 3π/2
  • B π/2
  • C
  • D π

Correct answer: A. 3π/2

Explanation: dI/dα = 0 gives tan(α) = α. The first solution (other than α=0) is approximately α = 3π/2 ≈ 4.49 rad. This gives the first secondary maximum.

Young's Double Slit Experimentsourceslits S₁,S₂dscreenbrightdarkPath difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes

Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.

Concept context

Huygens principle, Young's double slit, diffraction, polarization. Essential for JEE.

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