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⚛️ Physics  ·  Wave Optics  ·  NEET & JEE

In a Young double-slit experiment, λ = 600 nm, slit separation 1 mm, and screen distance 1 m. The fringe width is:

Answer: 0.6 mm.

  • A 0.06 mm
  • B 0.6 mm
  • C 1.2 mm
  • D 6 mm

Correct answer: B. 0.6 mm

Explanation: β = λD/d = 600×10⁻⁹·1/(10⁻³) = 6×10⁻⁴ m = 0.6 mm.

Young's Double Slit Experimentsourceslits S₁,S₂dscreenbrightdarkPath difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes

Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.

Concept context

Huygens principle, Young's double slit, diffraction, polarization. Essential for JEE.

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