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⚛️ Physics  ·  Wave Optics  ·  NEET & JEE

In a thin film of thickness t and refractive index n, the condition for constructive interference (reflected light) when light is incident from air is:

Answer: 2nt = (2m+1)λ/2 (half-wave loss at first surface).

  • A 2nt = (2m+1)λ/2 (half-wave loss at first surface)
  • B 2nt = mλ, the condition ignoring the half-wave phase loss
  • C 2t = mλ/n, omitting the refractive index from the optical path
  • D 2nt = mλ/2, half the correct optical path condition

Correct answer: A. 2nt = (2m+1)λ/2 (half-wave loss at first surface)

Explanation: At the top surface (denser medium), reflected ray has half-wave loss (π phase shift). At the bottom, no phase shift. For constructive interference: 2nt = (m + 1/2)λ, i.e., odd multiples of λ/2.

Young's Double Slit Experimentsourceslits S₁,S₂dscreenbrightdarkPath difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes

Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.

Concept context

Huygens principle, Young's double slit, diffraction, polarization. Essential for JEE.

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