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⚛️ Physics  ·  Wave Optics  ·  NEET & JEE

In a diffraction grating, for the n-th order spectrum of wavelength λ_1 to overlap with the (n+1)-th order of λ_2, we need:

Answer: nλ_1 = (n+1)λ_2.

  • A nλ_1 = (n+1)λ_2
  • B λ_1 = λ_2
  • C nλ_1 = nλ_2
  • D (n+1)λ_1 = nλ_2

Correct answer: A. nλ_1 = (n+1)λ_2

Explanation: For overlap: d sinθ must be equal. nλ_1 = (n+1)λ_2. This means λ_2 = nλ_1/(n+1). This is why free spectral range matters in spectroscopy.

Young's Double Slit Experimentsourceslits S₁,S₂dscreenbrightdarkPath difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes

Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.

Concept context

Huygens principle, Young's double slit, diffraction, polarization. Essential for JEE.

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