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⚛️ Physics  ·  Wave Optics  ·  NEET & JEE

If the 5th bright fringe in YDSE is at 2.5 mm from centre with D = 1 m and d = 1 mm, what is the wavelength?

Answer: 500 nm.

  • A 500 nm
  • B 250 nm
  • C 1000 nm
  • D 400 nm

Correct answer: A. 500 nm

Explanation: y<sub>n</sub> = nλD/d → λ = y<sub>n</sub> d/(nD) = (2.5×10⁻³ × 10⁻³)/(5 × 1) = 2.5×10⁻⁶/5 = 5×10⁻⁷ m = 500 nm.

Young's Double Slit Experimentsourceslits S₁,S₂dscreenbrightdarkPath difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes

Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.

Concept context

Huygens principle, Young's double slit, diffraction, polarization. Essential for JEE.

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