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⚛️ Physics  ·  Wave Optics  ·  NEET & JEE

A thin soap film (t = 400 nm, n = 1.33) is illuminated by white light. Which wavelength of reflected light is most intensified?

Answer: 424 nm (violet-blue).

  • A 424 nm (violet-blue)
  • B 532 nm (green)
  • C 700 nm (red)
  • D 800 nm (infrared)

Correct answer: A. 424 nm (violet-blue)

Explanation: Constructive reflection: 2nt = (m+1/2)λ. For m=1: λ = 2nt/(3/2) = 2×1.33×400/1.5 = 1064/1.5 ≈ 710 nm. For m=2: λ = 2×1.33×400/2.5 = 1064/2.5 ≈ 426 nm (violet).

Young's Double Slit Experimentsourceslits S₁,S₂dscreenbrightdarkPath difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes

Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.

Concept context

Huygens principle, Young's double slit, diffraction, polarization. Essential for JEE.

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