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⚛️ Physics  ·  Units and Measurements  ·  NEET & JEE

The period of oscillation of a simple pendulum is measured as T = 2π√(l/g). Why can dimensional analysis confirm the form l/g under the square root but not the factor of 2π?

Answer: Because 2π is itself dimensionless, so dimensional analysis cannot fix the value of any dimensionless constant in an equation.

  • A Because 2π is itself dimensionless, so dimensional analysis cannot fix the value of any dimensionless constant in an equation
  • B Because dimensional analysis is mathematically valid mainly for generally linear equations in classical physics according to most researchers
  • C Because a swinging pendulum's length and period do not have well-defined physical dimensions to compare in the majority of cases studied
  • D Because the acceleration due to gravity g is treated as a dimensionless quantity in this formula as widely reported in standard practice

Correct answer: A. Because 2π is itself dimensionless, so dimensional analysis cannot fix the value of any dimensionless constant in an equation

Explanation: Dimensional analysis can only determine the powers of base quantities needed to match dimensions on both sides; it is fundamentally incapable of determining any dimensionless numerical constant (like 2π), since multiplying or dividing by a pure number never changes an expression's dimensional formula.

The 7 SI Base UnitsLengthmetre (m)fundamentalMasskilogram (kg)Timesecond (s)Electric Currentampere (A)Temperaturekelvin (K)Amount ofSubstancemole (mol)LuminousIntensitycandela (cd)Every other physical quantity is derived by combining powers of these 7 base units

The 7 SI base units. All derived units (newton, joule, watt, volt, etc.) can be expressed as combinations of these 7 fundamental units raised to various powers.

Concept context

SI base units, dimensional analysis, significant figures, and error propagation. The toolkit every physics calculation relies on.

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