From the steady conduction relation Q/t = kA T/L, the dimensional formula of the thermal conductivity k is:

⚛️ Physics · Units and Measurements · NEET & JEE

From the steady conduction relation Q/t = kAΔT/L, the dimensional formula of the thermal conductivity k is:

Answer: [M L T -3 K -1 ].

A [M L2 T-3 K-1]
B [M L T-2 K-1]
C [M L T-3 K-1]
D [M L2 T-2 K-1]

Correct answer: C. [M L T-3 K-1]

Explanation: k = (Q/t)L/(AΔT) = [M L2 T-3][L]/([L2][K]) = [M L T-3 K-1].

The 7 SI base units. All derived units (newton, joule, watt, volt, etc.) can be expressed as combinations of these 7 fundamental units raised to various powers.

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From the steady conduction relation Q/t = kA&Delta;T/L, the dimensional formula of the thermal conductivity k is:

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From the steady conduction relation Q/t = kAΔT/L, the dimensional formula of the thermal conductivity k is: