Answer: 4200 J/(kg K).
- A 1 J/(kg K)
- B 420 J/(kg K)
- C 4200 J/(kg K)
- D 42000 J/(kg K)
Correct answer: C. 4200 J/(kg K)
Explanation: Specific heat of water = 4200 J/(kg K) = 4.2 J/(g K). Water has an unusually high specific heat.
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.