Answer: 1.32.
- A 0.76
- B 1.32
- C 1.4
- D 2
Correct answer: B. 1.32
Explanation: T₂/T₁ = (V₁/V₂)<sup>γ−1</sup> = 2<sup>0.4</sup> ≈ 1.32.
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.