Answer: 600 J.
- A 600 J
- B 1000 J
- C 400 J
- D 800 J
Correct answer: A. 600 J
Explanation: Over a cycle ΔU = 0, so W = net Q = (500 + 300) − 200 = 600 J.
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.