Answer: 100 J.
- A 0 J
- B 50 J
- C 100 J
- D 200 J
Correct answer: C. 100 J
Explanation: Over a cycle ΔU = 0, so by the first law Q = W = 100 J.
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.