Answer: 2 5/3.
- A 2
- B 2<sup>3/5</sup>
- C 2<sup>5/3</sup>
- D 3/5
Correct answer: C. 2<sup>5/3</sup>
Explanation: PV<sup>gamma</sup> = constant. P<sub>1</sub> V<sub>1</sub><sup>5/3</sup> = P<sub>2</sub> V<sub>2</sub><sup>5/3</sup>. V<sub>2</sub><sup>5/3</sup> = (P<sub>1</sub>/P<sub>2</sub>) V<sub>1</sub><sup>5/3</sup> = 2 V<sub>1</sub><sup>5/3</sup>. V<sub>2</sub> = 2<sup>3/5</sup> V<sub>1</sub>. Answer: 2<sup>3/5</sup>.
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.