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⚛️ Physics  ·  Thermodynamics  ·  NEET & JEE

Coefficient of performance (COP) of a refrigerator is:

Answer: Q cold /W.

  • A W/Q<sub>cold</sub>
  • B Q<sub>cold</sub>/W
  • C Q<sub>hot</sub>/W
  • D W/Q<sub>hot</sub>

Correct answer: B. Q<sub>cold</sub>/W

Explanation: COP = Q<sub>cold</sub>/W (heat removed from cold reservoir per unit work done). A good refrigerator has high COP.

Carnot Cycle (P-V Diagram)VP1→2: isothermal expansion (T_H)2→3: adiabatic expansion3→4: isothermal compression (T_C)4→1: adiabatic compression1234Net work done by the gas = area enclosed by the loop 1→2→3→4→1

The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.

Concept context

Laws of thermodynamics, heat engines, entropy, and gas processes.

Read the full Thermodynamics notes →