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⚛️ Physics  ·  Thermodynamics  ·  NEET & JEE

Carnot efficiency = 80%. If cold reservoir is at 400 K, hot reservoir is at:

Answer: 2000 K.

  • A 1600 K
  • B 2000 K
  • C 3200 K
  • D 800 K

Correct answer: B. 2000 K

Explanation: eta = 1 - T<sub>c</sub>/T<sub>h</sub>. 0.8 = 1 - 400/T<sub>h</sub>. 400/T<sub>h</sub> = 0.2. T<sub>h</sub> = 2000 K.

Carnot Cycle (P-V Diagram)VP1→2: isothermal expansion (T_H)2→3: adiabatic expansion3→4: isothermal compression (T_C)4→1: adiabatic compression1234Net work done by the gas = area enclosed by the loop 1→2→3→4→1

The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.

Concept context

Laws of thermodynamics, heat engines, entropy, and gas processes.

Read the full Thermodynamics notes →