Answer: 1200 K.
- A 600 K
- B 900 K
- C 1200 K
- D 2400 K
Correct answer: C. 1200 K
Explanation: T<sub>2</sub> = T<sub>1</sub>(V<sub>1</sub>/V<sub>2</sub>)<sup>γ−1</sup> = 300 × 8<sup>2/3</sup> = 300 × 4 = 1200 K.
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.