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⚛️ Physics  ·  Thermodynamics  ·  NEET & JEE

A gas absorbs 200 J of heat and does 150 J of work on its surroundings. The change in its internal energy is:

Answer: 50 J.

  • A 50 J
  • B 350 J
  • C −50 J
  • D 200 J

Correct answer: A. 50 J

Explanation: ΔU = Q − W = 200 − 150 = 50 J.

Carnot Cycle (P-V Diagram)VP1→2: isothermal expansion (T_H)2→3: adiabatic expansion3→4: isothermal compression (T_C)4→1: adiabatic compression1234Net work done by the gas = area enclosed by the loop 1→2→3→4→1

The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.

Concept context

Laws of thermodynamics, heat engines, entropy, and gas processes.

Read the full Thermodynamics notes →