Answer: 3741 J.
- A 300 J
- B 1247 J
- C 3741 J
- D 4988 J
Correct answer: C. 3741 J
Explanation: U = n Cv T = 1 x (3/2 x 8.314) x 300 = 3741 J. (T = 27+273 = 300 K)
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.