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⚛️ Physics  ·  Thermal Properties of Matter  ·  NEET & JEE

Two spheres of the same material, one of radius r and another of radius 2r, are heated to the same temperature and left to cool by radiation. The ratio of their rates of fall of temperature (dT/dt) initially, smaller to larger, is:

Answer: 2:1.

  • A 1:1
  • B 2:1
  • C 1:2
  • D 4:1

Correct answer: B. 2:1

Explanation: Rate of cooling dT/dt ∝ (surface area)/(volume) ∝ 1/r for spheres of the same material and temperature. Ratio of smaller to larger = (1/r):(1/2r) = 2:1.

Heating Curve: Ice → Water → SteamHeat added (Q)T (°C)ice warms (-ve→0°C)melting (0°C, latent heat)water warms (0→100°C)boiling (100°C, latent heat)FLAT regions = phase change (all heat goes into breaking bonds, NOT raising temperature)

During a phase change (melting or boiling), temperature stays constant while heat is absorbed entirely as latent heat (Q=mL); temperature only rises again once the substance is fully in its new phase.

Concept context

Temperature scales, thermal expansion, calorimetry, and the three modes of heat transfer including radiation laws.

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