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⚛️ Physics  ·  Thermal Properties of Matter  ·  NEET & JEE

Two rods of the same material and same length, but rod A has twice the cross-sectional area of rod B, conduct heat with the same temperature difference across their ends. The ratio of heat conducted per second by A to B is:

Answer: 2:1.

  • A 1:1
  • B 1:2
  • C 2:1
  • D 4:1

Correct answer: C. 2:1

Explanation: Rate of heat conduction H ∝ A (Fouriers law) for the same K, L, ΔT. Since A<sub>rod</sub> = 2×A<sub>rodB</sub>, ratio H<sub>A</sub>:H<sub>B</sub> = 2:1.

Heating Curve: Ice → Water → SteamHeat added (Q)T (°C)ice warms (-ve→0°C)melting (0°C, latent heat)water warms (0→100°C)boiling (100°C, latent heat)FLAT regions = phase change (all heat goes into breaking bonds, NOT raising temperature)

During a phase change (melting or boiling), temperature stays constant while heat is absorbed entirely as latent heat (Q=mL); temperature only rises again once the substance is fully in its new phase.

Concept context

Temperature scales, thermal expansion, calorimetry, and the three modes of heat transfer including radiation laws.

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