Zaymiey

⚛️ Physics  ·  Thermal Properties of Matter  ·  NEET & JEE

The heat required to melt 10 g of ice at 0°C (latent heat 80 cal/g) is:

Answer: 800 cal.

  • A 80 cal
  • B 336 cal
  • C 800 cal
  • D 8000 cal

Correct answer: C. 800 cal

Explanation: Q = mL = 10·80 = 800 cal.

Heating Curve: Ice → Water → SteamHeat added (Q)T (°C)ice warms (-ve→0°C)melting (0°C, latent heat)water warms (0→100°C)boiling (100°C, latent heat)FLAT regions = phase change (all heat goes into breaking bonds, NOT raising temperature)

During a phase change (melting or boiling), temperature stays constant while heat is absorbed entirely as latent heat (Q=mL); temperature only rises again once the substance is fully in its new phase.

Concept context

Temperature scales, thermal expansion, calorimetry, and the three modes of heat transfer including radiation laws.

Read the full Thermal Properties of Matter notes →