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⚛️ Physics  ·  Thermal Properties of Matter  ·  NEET & JEE

A rod conducts heat at a steady rate of 20 W when the temperature difference across its ends is 10°C. If the temperature difference is increased to 25°C (all else unchanged), the new rate of heat conduction is:

Answer: 50 W.

  • A 20 W
  • B 50 W
  • C 8 W
  • D 200 W

Correct answer: B. 50 W

Explanation: By Fouriers law, H ∝ ΔT for fixed K, A, L. New rate = 20 × (25/10) = 50 W.

Heating Curve: Ice → Water → SteamHeat added (Q)T (°C)ice warms (-ve→0°C)melting (0°C, latent heat)water warms (0→100°C)boiling (100°C, latent heat)FLAT regions = phase change (all heat goes into breaking bonds, NOT raising temperature)

During a phase change (melting or boiling), temperature stays constant while heat is absorbed entirely as latent heat (Q=mL); temperature only rises again once the substance is fully in its new phase.

Concept context

Temperature scales, thermal expansion, calorimetry, and the three modes of heat transfer including radiation laws.

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