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⚛️ Physics  ·  Thermal Properties of Matter  ·  NEET & JEE

A body cools from 60°C to 50°C in 10 minutes in surroundings at 30°C. Using Newton law of cooling, its temperature after the next 10 minutes is approximately:

Answer: 43.3°C.

  • A 40°C
  • B 43.3°C
  • C 45°C
  • D 48°C

Correct answer: B. 43.3°C

Explanation: First step: 1 = k(55 − 30) → k = 0.04. Next: (50 − T)/10 = 0.04((50 + T)/2 − 30) → T ≈ 43.3°C.

Heating Curve: Ice → Water → SteamHeat added (Q)T (°C)ice warms (-ve→0°C)melting (0°C, latent heat)water warms (0→100°C)boiling (100°C, latent heat)FLAT regions = phase change (all heat goes into breaking bonds, NOT raising temperature)

During a phase change (melting or boiling), temperature stays constant while heat is absorbed entirely as latent heat (Q=mL); temperature only rises again once the substance is fully in its new phase.

Concept context

Temperature scales, thermal expansion, calorimetry, and the three modes of heat transfer including radiation laws.

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