Answer: (3m+M/3)L²/4.
- A (3m+M/3)L²/4
- B ML²/12
- C (m+2m+M)L²/4
- D ML²/3
Correct answer: A. (3m+M/3)L²/4
Explanation: I = ML²/12 (rod about centre) + m(L/2)² + 2m(L/2)² = ML²/12 + mL²/4 + mL²/2 = ML²/12 + 3mL²/4.
Torque about axis O equals the force F multiplied by the perpendicular distance r⊥ from the axis to the line of action of the force, producing rotation.
Concept context
Moment of inertia, torque, angular momentum, rolling motion. Very high JEE weightage.
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