Answer: (2/3)g sin30°.
- A (2/3)g sin30°
- B (1/2)g sin30°
- C g sin30°
- D (3/4)g sin30°
Correct answer: A. (2/3)g sin30°
Explanation: For rolling without slipping, a = g sinθ/(1 + I/mR²). For solid cylinder, I = mR²/2, so a = g sinθ/(1 + 1/2) = (2/3)g sin30°.
Torque about axis O equals the force F multiplied by the perpendicular distance r⊥ from the axis to the line of action of the force, producing rotation.
Concept context
Moment of inertia, torque, angular momentum, rolling motion. Very high JEE weightage.
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