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⚛️ Physics  ·  System of Particles and Rotational Motion  ·  NEET & JEE

A particle of mass m moves in a plane. Its position vector is r = (t², 3t). What is the angular momentum about the origin at t = 1?

Answer: 3m - 6m = -3m (in z-direction).

  • A 3m - 6m = -3m (in z-direction)
  • B 3m, taking mainly the first term of the position-velocity cross product
  • C 6m, taking mainly the second term of the position-velocity cross product
  • D 0, mistakenly assuming the velocity and position vectors are parallel here

Correct answer: A. 3m - 6m = -3m (in z-direction)

Explanation: L = m(r × v). v = (2t, 3). At t=1: r = (1,3), v = (2,3). L<sub>z</sub> = m(rx vy - ry vx) = m(1×3 - 3×2) = m(3-6) = -3m.

axis OPr⊥Fττ = r⊥ × F = r × F × sinθ

Torque about axis O equals the force F multiplied by the perpendicular distance r⊥ from the axis to the line of action of the force, producing rotation.

Concept context

Moment of inertia, torque, angular momentum, rolling motion. Very high JEE weightage.

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