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⚛️ Physics  ·  Moving Charges and Magnetism  ·  NEET & JEE

The magnetic field at the centre of a circular coil of 50 turns, radius 0.05 m, carrying 2 A is (&mu;<sub>0</sub> = 4&pi; &times; 10<sup>-7</sup>):

Answer: 1.26 10 -3 T.

  • A 1.26 &times; 10<sup>-4</sup> T
  • B 6.28 &times; 10<sup>-4</sup> T
  • C 2.51 &times; 10<sup>-3</sup> T
  • D 1.26 &times; 10<sup>-3</sup> T

Correct answer: D. 1.26 &times; 10<sup>-3</sup> T

Explanation: B = &mu;<sub>0</sub>NI/(2R) = (4&pi; &times; 10<sup>-7</sup> &times; 50 &times; 2)/(2 &times; 0.05) = 4&pi; &times; 10<sup>-4</sup> &asymp; 1.26 &times; 10<sup>-3</sup> T.

Magnetic Field Lines Around a Straight WireIfield forms concentric circles around the wire (right-hand rule)

The magnetic field around a long straight current-carrying wire forms concentric circles, with direction given by the right-hand rule (point thumb along I, fingers curl in the direction of B).

Concept context

Magnetic force on moving charges and currents, the Biot-Savart law, Ampere's law, and the cyclotron - how electric currents create and respond to magnetic fields.

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